- Every rational number can be written as a terminating or repeating decimal.
- Addition: (a + b) = c, where a, b, and c are real numbers.
- Subtraction: (a - b) = c, where a, b, and c are real numbers.
- Multiplication: (a * b) = c, where a, b, and c are real numbers
.- Division: (a / b) = c, where a, b, and c are real numbers and b ≠ 0.
- For any two positive integers 'a' and 'b', there exist unique integers 'q' and 'r' such that a = bq + r, where 0 ≤ r < b.
- Every composite number can be expressed as a unique product of prime numbers, up to the order of the factors.
- The square of a number 'a' is denoted as (a^2).
- The square root of a number 'a' is denoted as (√a).
- Product law: a^m * a^n = a^(m+n), where 'a' is a non-zero real number and 'm' and 'n' are any real numb ers.
- Quotient law: a^m / a^n = a^(m-n), where 'a' is a non-zero real number and 'm' and 'n' are any real numb ers.
- Power law: (a^m)^n = a^(m*n), where 'a' is a non-zero real number and 'm' and 'n' are any real numbers.
- A number is irrational if it cannot be expressed as a fraction of two integers, and its decimal representati on never terminates or repeats.
- The decimal expansion of an irrational number is non-terminating and non-repeating.
- To convert a recurring decimal into a fraction, let 'x', the recurring decimal, be written as x = 0.abbb..., w here 'a' and 'b' are non-recurring and recurring digits, respectively.
Then, multiply 'x' by a suitable power o f 10 to eliminate the recurring part and subtract the original number from it, representing it algebraically. Fi nally, simplify the resulting equation to obtain the fraction.- The square root of a real number 'x' can be found using the long division method or using the iterative pr ocess of the Babylonian method.
1. Polynomial: A polynomial is an expression consisting of variables and coefficients combined using addit ion, subtraction, and multiplication operations.
2. Degree of a Polynomial: The degree of a polynomial is the highest power of the variable in the polynom ial.
3. Linear Polynomial: A polynomial of degree one is called a linear polynomial. It can be represented as a x + b, where a and b are constants.
4. Quadratic Polynomial: A polynomial of degree two is called a quadratic polynomial. It can be represente d as ax^2 + bx + c, where a, b, and c are constants.
5. Cubic Polynomial: A polynomial of degree three is called a cubic polynomial. It can be represented as a x^3 + bx^2 + cx + d, where a, b, c, and d are constants.
9. Coefficient: The coefficient is the numerical factor of each term in a polynomial. In the polynomial 5x^2 + 3x - 2, the coefficients are 5, 3, and -2.
10. Constant Term: The constant term is the term in a polynomial that does not have any variable. In the p olynomial 4x^2 + 3x - 2, the constant term is -2.
11. Zeroes/Roots of a Polynomial: The zeroes or roots of a polynomial are the values of the variable that s atisfy the polynomial equation and make it equal to zero.
12. Factor Theorem: According to the factor theorem, if a polynomial f(x) has a factor (x - a), then f(a) = 0.
13. Remainder Theorem: According to the remainder theorem, if a polynomial f(x) is divided by (x - a), the n the remainder will be f(a).
14. Fundamental Theorem of Algebra: The fundamental theorem of algebra states that any polynomial eq uation of degree greater than zero has at least one complex root.
15. Division Algorithm: The division algorithm states that any polynomial f(x) can be divided by a polynomi al g(x) where the degree of g(x) is less than or equal to the degree of f(x), resulting in a quotient q(x) and r emainder r(x) such that f(x) = g(x) * q(x) + r(x).
- Substitution Method:
- Solve one equation for one variable in terms of the other variable.
- Substitute the expression from step 1 into the other equation and solve for one variable.
- Substitute the value from step 2 into the expression found in step 1 and solve for the other variable.
- The values obtained in step 2 and 3 will be the solution to the pair of equations.
- Elimination Method:
- Multiply both equations by suitable numbers so that the coefficients of one variable are the same or ar e additive inverses.
- Add or subtract the equations to eliminate one variable and solve for the other variable.
- Substitute the value found in step 2 into one of the original equations and solve for the first variable.
- The values obtained in step 2 and 3 will be the solution to the pair of equations.
- Cross Multiplication Method for substitution:
- Solve one equation for one variable in terms of the other variable.
- Multiply both sides of the other equation by the denominator of the variable obtained in step 1.
- Equate the two expressions found in step 1 and 2 and solve for one variable.
- Substitute the value found in step 3 into the expression obtained in step 1 and solve for the other varia ble.
- The values obtained in step 3 and 4 will be the solution to the pair of equations.
- Consistent Equations: When the equations have a unique solution.
- Inconsistent Equations: When the equations have no solution.
- Dependent Equations: When the equations have infinitely many solutions.
i) If D > 0, the quadratic equation has two distinct real roots.
ii) If D = 0, the quadratic equation has two equal real roots.
iii) If D < 0, the quadratic equation has no real roots.
i) Sum of Roots (α + β) = -b/a
ii) Product of Roots (α * β) = c/a
- Using Heron's formula:
- Area = √(s(s-a)(s-b)(s-c)), where s is the semi-perimeter and a, b, c are the lengths of the sides of the triangle.
- Using the base and height:
- Area = 1/2 * base * height
- Using SAS (Side-Angle-Side) Formula:
- Area = 1/2 * a * b * sin(C), where a and b are the lengths of two sides of the triangle and C is the included angle.
- In a right-angled triangle, the square of the hypotenuse (longest side) is equal to the sum of the square s of the other two sides.
- a² + b² = c², where a, b are the lengths of the two shorter sides (legs) and c is the length of the hypotenuse.
- SSS (Side-Side-Side)
- SAS (Side-Angle-Side)
- ASA (Angle-Side-Angle)
- RHS (Right-Angle-Hypotenuse-Side)
- AAA (Angle-Angle-Angle)
- SSS (Side-Side-Side)
- SAS (Side-Angle-Side)
- The median is a line segment that joins a vertex of a triangle to the midpoint of the opposite side.
- In a triangle ABC, the medians are AD, BE, and CF.
- The medians divide each other in the ratio 2:1.
- The altitude is a perpendicular line segment drawn from a vertex of a triangle to the opposite side (or a n extension of it).
- An acute triangle has three altitudes, each starting from a different vertex and intersecting the opposite side.
- An obtuse triangle has one altitude outside the triangle.
7. Similarity of triangles and Pythagoras theorem with a proof.- Slope-intercept form: y = mx + c, where m is the slope and c is the y-intercept.
- Point-slope form: (y - y1) = m(x - x1), where m is the slope and (x1, y1) is a point on the line.
- Two-point form: (y - y1)/(y2 - y1) = (x - x1)/(x2 - x1), where (x1, y1) and (x2, y2) are two points on the lin e.
- Intercept form: x/a + y/b = 1, where a and b are the x and y-intercepts respectively.
- Two lines with slopes m1 and m2 are parallel if m1 = m2.
- Two lines with slopes m1 and m2 are perpendicular if m1 x m2 = -1.
- sin A = Perpendicular / Hypotenuse
- cos A = Base / Hypotenuse
- tan A = Perpendicular / Base
- cosec A = 1 / sin A = Hypotenuse / Perpendicular
- sec A = 1 / cos A = Hypotenuse / Base
- cot A = 1 / tan A = Base / Perpendicular
- sin² A + cos² A = 1
- 1 + tan² A = sec² A
- 1 + cot² A = cosec² A
- sin (90° - A) = cos A
- cos (90° - A) = sin A
- tan (90° - A) = cot A
- sec (90° - A) = cosec A
- cosec (90° - A) = sec A
- cot (90° - A) = tan A
- sin 30° = 1/2, cos 30° = √3/2, tan 30° = 1/√3
- sin 45° = cos 45° = 1/√2, tan 45° = 1
- sin 60° = √3/2, cos 60° = 1/2, tan 60° = √3
- sin (-A) = -sin A
- cos (-A) = cos A
- tan (-A) = -tan A
- sec (-A) = sec A
- cosec (-A) = -cosec A
- cot (-A) = -cot A
- sin (Π/2 ± A) = ± cos A
- cos (Π/2 ± A) = ± sin A
- tan (Π/2 ± A) = ± cot A
- sec (Π/2 ± A) = ± cosec A
- cosec (Π/2 ± A) = ± sec A
- cot (Π/2 ± A) = ± tan A
- Using sides: A = (1/2) * a * b * sin(C)
- Using base and height: A = (1/2) * b * h
- Using vertices: A = (1/2) * | x (y - y ) + x (y - y ) + x (y - y ) |
- Finding height using tangent: h = d * tan(θ)
- Finding distance using sine: d = h/sin(θ)
- Finding distance using cosine: d = h/cos(θ)
- Time period: T = 2π * √(L/g) Where T is the time period, L is the length of the pendulum, and g is acceleration due to gravity.
- Angle of Elevation: If a person is looking up at an object, the angle between the line of sight and the ho rizontal is called the angle of elevation.
- Angle of Depression: If a person is looking down at an object, the angle between the line of sight and t he horizontal is called the angle of depression.
- A = πr²
- Where A represents the area and r represents the radius of the circle
- C = 2πr
- Where C represents the circumference and r represents the radius of the circle
- d = 2r
- Where d represents the diameter and r represents the radius of the circle
- L = (θ/360) × 2πr
- Where L represents the length of the arc, θ represents the angle subtended by the arc at the center of the circle, and r represents the radius of the circle
- A = (θ/360) × πr²
- Where A represents the area of the sector, θ represents the angle subtended by the sector at the cent er of the circle, and r represents the radius of the circle
- c = 2r × sin(θ/2)
- Where c represents the chord length, θ represents the angle subtended by the chord at the center of t he circle, and r represents the radius of the circle
- t = √(d² - 4r²)
- Where t represents the length of the tangent, d represents the distance between the center of the circl e and the point of tangency, and r represents the radius of the circle
- The tangent to a circle is perpendicular to the radius drawn at the point of tangency
- Perpendicular bisector of a chord passes through the center of the circle
- The angle between a chord and a tangent at the point of contact is equal to the angle in the alternate s egment
- Step 1: Place the compass point on point A and extend the compass to a distance greater than half the l ength of AB.
- Step 2: With the compass still open to the same width, place the compass point on point B and draw an arc above and below AB.
- Step 3: Without changing the compass width, place the compass point on one of the intersections of the arcs and draw arcs that intersect the other arc.
- Step 4: Connect the two intersection points of the arcs to construct the perpendicular bisector of AB.
- Step 1: Place the compass point on point A and draw an arc that intersects both sides of the angle.
- Step 2: Without changing the compass width, place the compass point on each intersection point and dr aw arcs that intersect the other side of the angle.
- Step 3: Draw a straight line connecting point A to the intersection of the arcs. This is the angle bisector.
- Step 1: Place the compass point on the given point and extend the compass to a distance greater than t he distance from the point to the line.
- Step 2: With the compass still open to the same width, draw arcs that intersect the line at two points.
- Step 3: Without changing the compass width, place the compass point on each intersection point and dr aw arcs that intersect each other.
- Step 4: Connect the two intersection points of the arcs to construct the perpendicular from the point to th e line.
- Step 1: Draw a line segment with a length equal to the first given side.
- Step 2: From one of the endpoints of the first side, draw an arc with a radius equal to the second given si de.
- Step 3: From the other endpoint of the first side, draw another arc with a radius equal to the third given si de.
- Step 4: Connect the two intersection points of the arcs to form the triangle.
1. Circumference of a Circle: C = 2πr, where r is the radius of the circle.
2. Area of a Circle: A = πr², where r is the radius of the circle.
3. Diameter of a Circle: d = 2r, where r is the radius of the circle.
4. Length of an Arc: L = (θ/360) × 2πr, where θ is the central angle (in degrees) and r is the radius of the c ircle.
5. Area of a Sector: A = (θ/360) × πr², where θ is the central angle (in degrees) and r is the radius of the ci rcle.
6. Area of a Segment: A = A[sector] - A[triangle], where A[sector] is the area of the corresponding sector a nd A[triangle] is the area of the corresponding triangle.
7. Chord Length Formula: l = 2r × sin(θ/2), where r is the radius of the circle and θ is the central angle (in degrees) formed by the chord.
8. Perpendicular from the Center to a Chord: The perpendicular drawn from the center of a circle to a chor d bisects the chord.
9. Tangent to a Circle: A tangent to a circle is perpendicular to the radius drawn to the point of tangency.
10. Length of a Tangent: LT = √(LS × LT'), where LS is the length of the secant segment and LT' is the len gth of the external segment.
1. Surface Area of Cube = 6a² (where 'a' is the length of a side)
2. Volume of Cube = a³ (where 'a' is the length of a side)
3. Surface Area of Cuboid = 2(lw + lh + wh) (where 'l' is the length, 'w' is the width, and 'h' is the height)
4. Volume of Cuboid = lwh (where 'l' is the length, 'w' is the width, and 'h' is the height)
5. Surface Area of Right Circular Cylinder = 2πrh + 2πr² (where 'r' is the radius and 'h' is the height)
6. Volume of Right Circular Cylinder = πr²h (where 'r' is the radius and 'h' is the height)
7. Surface Area of Sphere = 4πr² (where 'r' is the radius)
8. Volume of Sphere = (4/3)πr³ (where 'r' is the radius)
9. Surface Area of Hemisphere = 2πr² (where 'r' is the radius)
10. Volume of Hemisphere = (2/3)πr³ (where 'r' is the radius)
11. Curved Surface Area of Cone = πrl (where 'r' is the radius and 'l' is the slant height)
12. Total Surface Area of Cone = πr(r + l) (where 'r' is the radius and 'l' is the slant height)
13. Volume of Cone = (1/3)πr²h (where 'r' is the radius and 'h' is the height)
14. Surface Area of Frustum of Cone = π(R + r)(l) + πR² + πr² (where 'R' is the radius of the upper base, 'r ' is the radius of the lower base, and 'l' is the slant height)
15. Volume of Frustum of Cone = (1/3)πh(R² + r² + Rr) (where 'R' is the radius of the upper base, 'r' is the radius of the lower base, and 'h' is the height)
1) If the number of observations is odd:
Median = Value of (N + 1) / 2 th observation Symbolically: Median = X[(N + 1) / 2]2) If the number of observations is even:
Median = (Value of (N / 2)th observation + Value of ((N / 2) + 1)th observation) / 2 Symbolically: Median = (X[N / 2] + X[(N / 2) + 1]) / 2L = Lower boundary of the modal class
f1 = Frequency of the modal class
f0 = Frequency of the class before the mode class
f2 = Frequency of the class after the mode class
c = Width of the modal class
1st Quartile (Q ) = (n + 1) / 4 th term
3rd Quartile (Q ) = 3(n + 1) / 4 th term
Interquartile Range = Q - Q
Variance = Sum of (Xi - )² / N
Symbolically: σ² = Σ(Xi - )² / N
Standard Deviation = √Variance
Symbolically: σ = √(Σ(Xi - )² / N)
Correlation Coefficient = Covariance / (Standard Deviation of X ×
Standard Deviation of Y)
Symbolically: r = Σ((Xi - ) × (Yi - y )) / √(Σ(Xi - )² × Σ(Yi - y )²)